question_answer 58)

                  The position time graph of a body of mass 2 kg is as given in Fig. What is the impulse on die body at \[t=0\,s\] and \[t=4\,s\].

Answer:

                  Impulse \[=Ft=0\] at \[t=0\]                 At \[t=4,\text{ }u=0,\,\upsilon =\,\frac{3}{4}\,\,m{{s}^{-1}}\]                 \[\therefore \] Impulse = change in momentum \[=\,m\,(m-\upsilon )\]                 \[=2\left( 0-\frac{3}{4} \right)\,=-\frac{3}{2}\,\,kg\,\,m{{s}^{-1}}\,\,=-\frac{3}{2}\,Ns\]