question_answer 57)

                  A person of mass 50 kg stands oil a weighing scale oil a lift. If die lift is descending with a downward acceleration of \[9\,m\,{{s}^{-2}}\], what would be the reading of the weighing scale? \[(g=10\,m\,{{s}^{-2}})\]

Answer:

                  \[ma=mg-R\]                 or \[R=m(ga)=50(10-9)=50\text{ }N\]                 \ Reading of weighing scale \[=\frac{50}{100}\,=5\,kg.\]