Answer:
Here, \[m=\,50\,kg'\,r=D/2=\frac{1}{2}\,cm=\theta m\]
Pressure \[=\theta ={{90}^{o}}\] i.e.,
\[1\cdot 0\times
{{10}^{3}}kg{{m}^{-3}}\left( g=9\cdot 8m{{s}^{-2}} \right).\]
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