Answer:
(a) When we blow over the paper, the velocity of air blow
increases and hence pressure of air on it decreases (according to Bernoullis
Theorem), where as pressure of air below the paper is atmospheric. Hence, the
paper stays horizontal.
(b)
By doing so the area of outlet of water jet is reduced, so velocity of water
increases according to equation of continuity, \[\frac{2S\cos \theta }{r\rho
g}=\frac{2\times 0\cdot 465\times \cos {{140}^{o}}}{{{10}^{-3}}\times 13\cdot
6\times {{10}^{3}}\times 9\cdot 8}\]
(c)
When a fluid is flowing out of a small hokle in a vessel, it acquires a large
velocity and hence possesses large momentum. Since no external force is acting
on the system, a backward velocity must be attained by the vessel (according to
low of conservation of momentum). As a result of it, an impulse (backward
thrust) is experienced by the vessel is experienced by the vessel.
(d) Here, size of the needle controls
velocity of flow and thumb pressure controls pressure. According to Bernoullis
theorem, \[\frac{2\times 0\cdot 465\times \left( -0\cdot 7660
\right)}{{{10}^{-3}}\times 13\cdot 6\times {{10}^{3}}\times 9\cdot 8}=-5\cdot
34\times {{10}^{-3}}m=-5\cdot 34mm\]constant shows that p occurs with power one
and\[\cdot \] occurs with power two, hence the velocity has more influence.
That is why the needle has a better control over flow.
(e) See Art. 7(c). 16 part (4). [i.e. curved
motion of spinning ball].
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