Answer:
\[\lambda =\frac{h}{m\upsilon
}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,.......(i)\]
\[h=6.626\times {{10}^{-34}}Js\]
\[m=1.675\times {{10}^{-27}}kg\]
(mass of neutron)
\[\lambda =800\times {{10}^{-12}}pm\]
Substituting these values in
Eqn. (i)
\[\upsilon
=\frac{h}{\lambda m}\]
\[=\frac{6.626\times
{{10}^{-34}}}{800\times {{10}^{-12}}1.675\times {{10}^{-27}}}\]
\[=494.47m\,{{s}^{-1}}\]
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