question_answer 76)

Dual behaviour of matter proposed by de Broglie led to the discovery of electron microscope often used for the highly magnified images of biological molecules and other types of material. If the velocity of electron in this microscope is \[1.6\times {{10}^{6}}m\,{{s}^{-1}}\], calculate the de Broglie wavelength associated with this electron.

Answer:

\[\lambda =\frac{h}{m\upsilon }\] \[=\frac{6.626\times {{10}^{-34}}}{9.1\times {{10}^{-31}}\times 1.6\times {{10}^{6}}}\] \[=455\times {{10}^{-12}}m\] \[=455pm\]