question_answer 53)

Calculate the energy required for the process, \[H{{e}^{+}}(g)\to H{{e}^{2+}}(g)+{{e}^{-}}\] The ionization energy for H-atom in the ground state is \[2.18\times {{10}^{-18}}J\,ato{{m}^{-1}}.\]

Answer:

\[\frac{{{I}_{H}}}{{{I}_{H{{e}^{+}}}}}\frac{Z_{H}^{2}}{Z_{H{{e}^{+}}}^{2}}\] \[\frac{2.18\times {{10}^{-18}}}{{{I}_{H{{e}^{+}}}}}=\frac{{{1}^{2}}}{{{2}^{2}}}\] \[{{I}_{H{{e}^{+}}}}=8.72\times {{10}^{-18}}Jato{{m}^{-1}}\]