question_answer 54)

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in straight line across the length of scale of 20 cm long.

Answer:

Let x atoms are placed on the scale of length 20cm. \[x\] x diameter = 20 cm \[x\times 0.15\times {{10}^{-7}}=20\] \[x=\frac{20}{0.15\times {{10}^{-7}}}=1.33\times {{10}^{9}}atoms\]