Answer:
Frequency \[(v)=\frac{1}{\text{Time}\,\text{period}\,(T)}\]
\[=\frac{1}{2\times
{{10}^{-10}}}{{\sec }^{-1}}=5\times {{10}^{9}}Hz\]
\[v=\frac{c}{\lambda }\]
\[\lambda =\frac{c}{v}=\frac{3\times
{{10}^{8}}}{5\times {{10}^{9}}}\]
\[=0.06m\]
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