Answer:
(i) \[E=hv\]
\[=(6.626\times {{10}^{-34}}Jsec)\times
(3\times {{10}^{15}}se{{c}^{-1}})\]
\[=1.9878\times {{10}^{-18}}J\]
(ii) \[E=\frac{hc}{\lambda }=\frac{(6.626\times {{10}^{-34}}\,J\,\sec
)\times (3\times {{10}^{8}}\,m\,{{\sec }^{-1}})}{0.5\times {{10}^{-10}}\,m}\]
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