question_answer 51)

  What will be the molality of the solution containing 18.25 g of HCl gas in 500 g of water? (a) 0.1 m                              (b) 1 M (c) 0.5 m                               (d) 1 m

Answer:

  (d) Molality, \[m=\frac{{{w}_{B}}\times 1000}{{{m}_{B}}\times {{w}_{A}}}\] \[{{w}_{B}}=18.25g,\,\,\,\,{{m}_{B}}=36.5g\,mo{{l}^{-1}}\,,\,\,\,\,\,\,{{w}_{A}}=500g\] \[\therefore \]                  \[m=\frac{18.25\times 1000}{36.5\times 500}=1\]