11th Class Chemistry Some Basic Concepts of Chemistry

  • question_answer 52)
      One mole of any substance contains \[6.022\times {{10}^{23}}\] atoms/molecules. Number of molecules of  present in 100 mL of 0.02 M \[{{H}_{2}}S{{O}_{4}}\] solution is : (a) \[12.044\times {{10}^{20}}\] molecules (b) \[6.022\times {{10}^{23}}\] molecules (c) \[1\times {{10}^{23}}\] molecules (d) \[12.044\times {{10}^{23}}\] molecules


    (a) Number of moles of \[{{H}_{2}}S{{O}_{4}}=\frac{MV}{1000}\] \[=\frac{0.02\times 100}{1000}=0.002\] Number of molecules of \[{{H}_{2}}S{{O}_{4}}=0.002\times 6.023\times {{10}^{23}}\] \[=1.246\times {{10}^{21}}\]

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