question_answer 60)

In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

Answer:

% of sulphur = \[\frac{32}{233}\times \frac{Mass\,of\,BaS{{O}_{4}}\,formed}{Mass\,of\,the\,\text{substance}}\times 100\] \[=\frac{32}{233}\times \frac{0.668}{0.468}\times 100=\mathbf{19}\mathbf{.60%}\]