question_answer 61)

In the organic compound \[{{H}_{2}}C=CHC{{H}_{2}}C{{H}_{2}}C=CH\], the pair of hybridised orbitals involved in the formation of\[{{C}_{2}}-{{C}_{3}}\] bond is: (a) \[sp-s{{p}^{2}}\] (b) \[sp-s{{p}^{3}}\] (c)\[s{{p}^{2}}-s{{p}^{3}}\] (d)\[~s{{p}^{3}}-s{{p}^{3}}\]  

Answer:

(c) is the correct answer, i.e., \[s{{p}^{2}}-s{{p}^{3}}\]orbital because the name of the organic compound is : \[{{H}_{2}}\underset{s{{p}^{2}}}{\overset{1}{\mathop{C}}}\,=\underset{s{{p}^{2}}}{\overset{2}{\mathop{C}}}\,H-\underset{s{{p}^{3}}}{\overset{3}{\mathop{C}}}\,{{H}_{2}}-\underset{s{{p}^{3}}}{\overset{4}{\mathop{C}}}\,{{H}_{2}}-\underset{sp}{\overset{5}{\mathop{C}}}\,\equiv \underset{sp}{\overset{6}{\mathop{C}}}\,H(Hex-1-en-5-yr)\]