Answer:
\[C{{O}_{2}}\] is slightly
soluble in water forming carbonic acid.
\[C{{O}_{2}}+{{H}_{2}}O\to
{{H}_{2}}C{{O}_{3}}\]
The oxides of nitrogen undergo
oxidation reaction followed by reaction with water vapours to form nitric acid.
\[NO+{{O}_{2}}\xrightarrow{{}}2N{{O}_{2}}\]
\[2N{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}HN{{O}_{3}}+HN{{O}_{2}}\]
The oxidation of \[S{{O}_{2}}\]
into \[S{{O}_{3}}\] in presence of dust particles or metal ions. The \[S{{O}_{3}}\]
then reacts with water vapours to form\[{{H}_{2}}S{{O}_{4}}\].
\[2S{{O}_{2}}+{{O}_{2}}\xrightarrow[or\,metal\,ions]{Dust\,particles}2S{{O}_{3}}\]
\[S{{O}_{3}}+{{H}_{2}}O\xrightarrow{{}}{{H}_{2}}S{{O}_{4}}\]
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