WB JEE Medical WB JEE Medical Solved Paper-2014

  • question_answer
    \[_{98}C{{f}^{246}}\]was formed along with a neutron when an unknown radioactive substance was bombarded with \[{{\,}_{6}}{{C}^{12}}.\]The unknown substance was

    A)  \[{{\,}_{91}}P{{a}^{234}}\]

    B)  \[{{\,}_{90}}T{{h}^{234}}\]

    C)  \[{{\,}_{92}}{{U}^{235}}\]

    D)  \[{{\,}_{92}}{{U}^{238}}\]

    Correct Answer: C

    Solution :

     Let, the unknown radioactive Substance be \[{{\,}_{x}}{{A}^{y}}.\] \[{{\,}_{x}}{{A}^{y}}+{{\,}_{6}}{{C}^{12}}\xrightarrow{{}}{{\,}_{98}}C{{f}^{246}}+{{\,}_{0}}{{n}^{1}}\] On comparing atomic numbers, we get \[x+6=98+0\] \[x=98-6=92\] On comparing mass numbers, we get \[Y+12=246+1\] \[Y=247-12\] \[=235\] Since, uranium has the atomic number 92, thus, the given unknown substance was \[{{\,}_{92}}{{U}^{235}}.\]


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