WB JEE Medical WB JEE Medical Solved Paper-2014

  • question_answer
    For one mole of an ideal gas, the slope of \[V\upsilon s.\]T curve at constant pressure of 2 aim is \[X\,L\,mo{{l}^{-1}}\,{{K}^{-1}}.\]The value of the ideal universal gas constant R in terms of X is

    A) \[X\text{ }L\text{ }atm\text{ }mo{{l}^{-1}}{{K}^{-1}}\]  

    B)  \[\frac{X}{2}\text{ }L\text{ }atm\text{ }mo{{l}^{-1}}{{K}^{-1}}\]

    C) \[2X\text{ }L\text{ }atm\text{ }mo{{l}^{-1}}{{K}^{-1}}\] 

    D)  \[2X\,atm\,{{L}^{-1}}\,mo{{l}^{-1}}{{K}^{-1}}\]

    Correct Answer: C

    Solution :

     Ideal gas equation is \[pV=nRT\]or \[V=\frac{nRT}{p}+C\] or   \[V=\frac{RT}{p}+0\] (for 1 mol) When \[V\,vs\]T is plotted, a straight line is obtained, slope of which is given by R/ p. \[\text{Slope}=\frac{R}{p}\Rightarrow \,\,X=\frac{R}{2}\] or \[R=2\,X\,L\,\text{atm}\,\text{mo}{{\text{l}}^{-}}{{\text{K}}^{-1}}\]


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