A) \[5l\]and\[3l\]
B) \[9l\] and\[3l\]
C) \[4l\] and\[l\]
D) \[9l\]and\[l\]
Correct Answer: D
Solution :
We know that The maximum intensities \[{{I}_{\max }}={{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}\] ?(i) The minimum intensities \[{{I}_{\min }}={{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}\] ?(ii) So, the ratio of the maximum and minimum of intensities is \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}}{{{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}}\] \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{(\sqrt{4I}+\sqrt{I})}^{2}}}{{{(\sqrt{4I}-\sqrt{I})}^{2}}}\] \[={{\left( \frac{3\sqrt{I}}{\sqrt{I}} \right)}^{2}}\] \[=\frac{9}{1}=9:1\]
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