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WB JEE Medical WB JEE Medical Solved Paper-2014

  • question_answer
    The intensity of magnetization of a bar magnet is \[5.0\times {{10}^{4}}A{{m}^{-1}}.\] The magnetic length and the area of cross-section of the magnet are 12 cm and \[1\text{ }c{{m}^{2}}\]respectively. The magnitude of magnetic moment of this bar magnet is (in SI unit)

    A)  0.6    

    B)  1.3   

    C)  1.24

    D)  2.4

    Correct Answer: A

    Solution :

     We know that Intensity of magnetization \[I=\frac{M}{V}\]  [where M = magnetic moment, V = volume] So   \[M=IV=5.0\times {{10}^{4}}\times \frac{12}{100}\times \frac{1}{{{(100)}^{2}}}\] \[=60\times {{10}^{4}}\times {{10}^{-6}}=0.6\,A{{m}^{2}}\]


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