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WB JEE Medical WB JEE Medical Solved Paper-2014

  • question_answer
    The compressibility factor (Z) of one mole of a van der Waals gas of negligible a value is

    A)  1

    B)  \[\frac{bp}{RT}\]

    C)  \[1+\frac{bp}{RT}\]

    D)  \[1-\frac{bp}{RT}\]

    Correct Answer: C

    Solution :

     van der Waals equation is \[\left( p+\frac{a}{{{V}^{2}}} \right)(V-b)=RT\] (for 1 mole) If a is negligible, \[p+\frac{a}{{{V}^{2}}}\approx p\] \[p(V-b)=RT\Rightarrow pV-pb=RT\] or \[\frac{PV}{RT}-\frac{pb}{RT}=1\Rightarrow \frac{pV}{RT}=1+\frac{pb}{RT}\]


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