A) \[{{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}\]
B) \[{{[{{(NiCN)}_{4}}]}^{2-}}\]
C) \[TiC{{l}_{4}}\]
D) \[{{[CoC{{l}_{6}}]}^{4-}}\]
Correct Answer: A
Solution :
Magneitc moment, \[\mu \]is related with number of unpaired electrons as \[\mu =\sqrt{n(n+2)}BM\] \[{{(1.73)}^{2}}=n(n+2)\] On solving \[n=1\] Thus, the complex/compound having one unpaired electron exhibit a magnetic moment of 1.73 BM. [a] ln \[{{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}\] \[C{{u}^{2+}}=[Ar]\,3{{d}^{9}}\]You need to login to perform this action.
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