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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    Equal weights of \[C{{H}_{4}}\]and \[{{H}_{2}}\]are mixed in an empty container at \[25{{\,}^{o}}C.\]the fraction of the total pressure exerted by \[{{H}_{2}}\] is

    A)  1/9             

    B)  1/2

    C)  8/9             

    D)  16/17

    Correct Answer: C

    Solution :

     Ratio of number of moles of \[C{{H}_{4}}\]and \[{{H}_{2}}\]are \[C{{H}_{4}}:{{H}_{2}}=\frac{x}{16}:\frac{x}{2}=1:8\] Hence, partial pressure exerted by \[{{H}_{2}}=\frac{8}{1+8}\times {{p}_{total}}=\frac{8}{9}\times {{p}_{total}}\]


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