A) two unpaired electrons in \[{{\pi }_{b}}\,MO\]
B) two unpaired electrons in \[\overset{*}{\mathop{\pi }}\,\,MO\]
C) two unpaired electrons in \[\overset{*}{\mathop{\sigma }}\,MO\]
D) two unpaired electrons in \[{{\sigma }_{b}}MO\]
Correct Answer: A
Solution :
\[{{B}_{2}}=5+5={{10}^{-e}}\] \[=\sigma 1{{s}^{2}}\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}}\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\pi 2p_{x}^{1},\pi 2p_{y}^{1}\] Due to the presence of 2 unpaired electrons, in \[\pi \] bonding orbitals, \[{{B}_{2}}\] shows paramagnetic behaviour.
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