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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    A particle is projected from the ground with a kinetic energy E at an angle of \[{{60}^{o}}\] with the horizontal. Its kinetic energy at the highest point of its motion will be

    A)  \[E/\sqrt{2}\]

    B)  \[E/2\]

    C)  \[E/4\]

    D) \[E/8\]

    Correct Answer: C

    Solution :

     At ground, \[E=\frac{1}{3}m{{u}^{2}}\] At highest point,\[E=\frac{1}{2}m{{(u\,cos{{60}^{o}})}^{2}}\] \[E=\frac{E}{4}\]


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