A) \[C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}CH=CHC{{H}_{3}}\]
C) \[{{(C{{H}_{3}})}_{2}}C=C{{H}_{2}}\]
D) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
Correct Answer: C
Solution :
Iso-butylene directly add a molecule of water in presence of \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]as catalyst to form tertiary butyl alcohol. \[\underset{\begin{smallmatrix} Iso-butylene \\ (2-methylpropene) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,\xrightarrow{{{H}^{+}}}C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\underset{+}{\overset{|}{\mathop{C}}}\,}}\,-C{{H}_{3}}\xrightarrow{{{H}_{2}}\underset{\centerdot \,\,\centerdot }{\overset{\centerdot \,\,\centerdot }{\mathop{O}}}\,}\]
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