WB JEE Medical WB JEE Medical Solved Paper-2010

  • question_answer
    A spring of force constant k is cut into three equal parts. The force constant of each part would be

    A)  \[\frac{k}{3}\]                                  

    B)  \[3k\]

    C)  \[k\]                                    

    D)  \[2k\]

    Correct Answer: B

    Solution :

                     The force constant is inversely proportional to the length of the spring. Since, the spring has been divided into three parts, so the length of each part becomes one third of the length. Thus, the spring constant of each part would be three times the spring constant of the complete spring.


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