2. Solved Papers
  3. WB JEE Medical

WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    What is the particle X in the following nuclear reaction\[_{4}^{9}Be+_{2}^{4}He\xrightarrow{{}}_{6}^{12}C+X\]

    A)  Electron                             

    B)  Proton

    C)  Photon                               

    D)  Neutron

    Correct Answer: D

    Solution :

                     \[_{4}^{9}Be+_{2}^{4}He\xrightarrow[{}]{{}}\,_{6}^{12}C+_{z}^{A}X\] Comparing sum of mass numbers and atomic numbers on both sides, we get \[A=1,Z=0\] Hence, X represents \[_{0}^{1}n\] (neutron).


You need to login to perform this action.
You will be redirected in 3 sec spinner