WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    At a certain place, the horizontal component of earths magnetic field is \[\sqrt{3}\] times the vertical component. The angle of dip at that place is

    A)  \[\text{3}{{\text{0}}^{\text{o}}}\]                                          

    B)  \[\text{6}{{\text{0}}^{\text{o}}}\]

    C)  \[{{45}^{\text{o}}}\]                                     

    D)  \[\text{9}{{\text{0}}^{\text{o}}}\]

    Correct Answer: A

    Solution :

                     Angle of dip,\[\theta ={{\tan }^{-1}}\left( \frac{V}{H} \right)={{\tan }^{-1}}\left( \frac{1}{\sqrt{3}} \right)={{30}^{o}}\]


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