question_answer

Which one of the following gives, on ozonolysis, both aldehydes and ketones?

A)  \[M{{e}_{2}}C=CHMe\]               

B)  \[M{{e}_{2}}C=CM{{e}_{2}}\]

C)  \[MeC{{H}_{2}}-C(Me)=CM{{e}_{2}}\]

D)  \[MeCH(Me)-CH=CHMe\]

Correct Answer: A

Solution :

                  \[\xrightarrow{Zn/C{{H}_{3}}COOH}\underset{\text{ketone}}{\mathop{Me-\overset{O}{\mathop{\overset{|\,\,|}{\mathop{C}}\,}}\,-}}\,Me+\underset{\text{aldehyde}}{\mathop{Me-\overset{O}{\mathop{\overset{|\,\,|}{\mathop{C}}\,}}\,-H}}\,\]