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WB JEE Medical WB JEE Medical Solved Paper-2008

  • question_answer
    The product p of the nuclear reaction\[_{92}^{235}U_{0}^{1}n\xrightarrow{{}}p+_{36}^{92}Kr+3_{0}^{1}n,\]is

    A)  \[_{56}^{141}Sr\]                           

    B)  \[_{56}^{141}La\]

    C)  \[_{56}^{141}Ba\]                          

    D)  \[_{56}^{141}Cs\]

    Correct Answer: C

    Solution :

                     The complete nuclear reaction is\[_{92}^{235}U+{{\,}_{0}}{{n}^{1}}\xrightarrow{{}}_{56}^{141}Ba+_{36}^{92}Kr+3_{0}^{1}n\] 


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