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WB JEE Medical WB JEE Medical Solved Paper-2008

  • question_answer
    In the reaction \[3A\xrightarrow{{}}2B,\] rate of reaction \[+\frac{d(B)}{dt}\] is equal to

    A)  \[-\frac{1}{3}\frac{d[A]}{dt}\]                  

    B)  \[-\frac{2}{3}\frac{d[A]}{dt}\]

    C)  \[+\frac{2d[A]}{dt}\]                    

    D)  \[-\frac{3}{2}+\frac{d[A]}{dt}\]

    Correct Answer: B

    Solution :

                     For the reaction, \[3A\xrightarrow{{}}2B\] \[\text{Rate}=-\frac{1}{3}\frac{d[A]}{dt}=+\frac{1}{2}\frac{d[B]}{dt}\]                 \[\therefore \]                  \[+\frac{d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt}\]


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