A) 1.0 L of nitrogen
B) 22.4 L of nitrogen
C) 11.2 L of nitrogen
D) 5.6 L of nitrogen
Correct Answer: B
Solution :
\[C{{H}_{3}}-N{{H}_{2}}+HN{{O}_{2}}\xrightarrow{{}}C{{H}_{3}}OH+{{N}_{2}}+{{H}_{2}}O\]1 mole of methyl amine gives 1 mole \[{{N}_{2}}\] ie, 22.4 L of nitrogen at NTP.
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