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WB JEE Medical WB JEE Medical Solved Paper-2008

  • question_answer
    Sodium nitrate on reduction with Zn in presence of NaOH solution produces \[\text{N}{{\text{H}}_{\text{3}}}\text{.}\]Mass of sodium nitrate absorbing Imole of electron will be

    A)  7.750                                   

    B)  10.625

    C)  8.000                                   

    D)  9.875

    Correct Answer: B

    Solution :

                     Required equation is given below, \[Zn+2O{{H}^{-}}\xrightarrow{{}}ZnO_{2}^{2-}+2{{H}^{+}}+2{{e}^{-}}\] \[NO_{3}^{-}+8{{H}^{+}}+8{{e}^{-}}\xrightarrow{{}}O{{H}^{-}}+2{{H}_{2}}O+N{{H}_{3}}\] From the above equation \[\because \] 8 moles of electron absorbed by 85 g of \[\text{NaN}{{\text{O}}_{\text{3}}}\] \[\therefore \]1 mole of electron absorbed by \[\frac{85}{8}g\]of \[\text{NaN}{{\text{O}}_{\text{3}}}\] \[=10.625\,\,g\]


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