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WB JEE Medical WB JEE Medical Solved Paper-2008

  • question_answer
    The brown complex obtained in the detection of nitrate    radical    is    formulated    as \[\text{ }\!\![\!\!\text{ Fe(}{{\text{H}}_{2}}\text{O}{{\text{)}}_{5}}\text{NO }\!\!]\!\!\text{ S}{{\text{O}}_{4}}.\]What is the oxidation number of Fe in this complex?

    A)  +1                                         

    B)  +2

    C)  +3                                         

    D)  0

    Correct Answer: A

    Solution :

                     The brown colour complex obtained in the detection of nitrate radical is formulated as \[[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}},\] In this complex, oxidation state of iron is +1. The univalent character of iron in the complex is justified by  the presence of a coordinated \[\text{N}{{\text{O}}^{\text{+}}}\]group.


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