A) \[64q,C\]
B) \[16q,4C\]
C) \[64q,4C\]
D) \[16q,64C\]
Correct Answer: C
Solution :
64 drops have formed a single drop of radius R. Volume of big drop = Volume of smalls drop. \[\therefore \] \[\frac{4}{3}\pi {{R}^{3}}=64\times \frac{4}{3}\pi {{r}^{3}}\] \[\Rightarrow \] \[R=4r\] So, the total current is \[{{Q}_{total}}=64q\] As \[C=\frac{Q}{V}\]and \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{R};C=4\pi {{\varepsilon }_{0}}R\] \[C=(4\pi {{\varepsilon }_{0}})4r\Rightarrow C=4C.\]
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