WB JEE Medical WB JEE Medical Solved Paper-2008

  • question_answer
    The ionisation potential of hydrogen atom is -13.6 eV. An electron in the ground state of a hydrogen atoms absorbs a photon of energy 12.75 eV. How many different spectral line can one expect when the electron make a downward transition?

    A)  1                                            

    B)  4

    C)  2                                            

    D)  6

    Correct Answer: D

    Solution :

                     \[E={{E}_{1}}/{{n}^{2}}\] Energy used for excitation is 12.75 eV ie, \[(-13.6+12.75)eV=-0.85\,eV\] Energy levels of H-atom The photons of energy 12.75 eV can excite the fourth level of H-atom. Therefore, six lines will be emitted, \[\left( n\left( \frac{(n-1)}{2} \right)\text{lines} \right).\]


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