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WB JEE Medical WB JEE Medical Solved Paper-2008

  • question_answer
    Two tuning forks of frequency \[{{n}_{1}}\]and \[{{n}_{2}}\]produces n beats per second. If \[{{n}_{2}}\]and n are known, \[{{n}_{1}}\]may be given by

    A)  \[\frac{{{n}_{2}}}{n}+{{n}_{2}}\]                              

    B)  \[{{n}_{2}}n\]

    C)  \[{{n}_{2}}\pm n\]                         

    D)  \[\frac{{{n}_{2}}}{n}-{{n}_{2}}\]

    Correct Answer: C

    Solution :

                     Beat frequency = number of beats/sec. \[n={{n}_{2}}\pm {{n}_{1}}\]                 \[\therefore \]  \[{{n}_{1}}={{n}_{2}}\pm n\]


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