A) 2:1
B) 1:2
C) 1 : 1
D) 1 : 4
Correct Answer: C
Solution :
Frequency is given by \[v=\frac{1}{2l}\sqrt{\frac{T}{\mu }}\] \[\therefore \] First frequency \[{{v}_{1}}=\frac{1}{2l}\sqrt{\frac{T}{\mu }}\] and second frequency \[{{v}_{2}}=\frac{1}{4l}\sqrt{\frac{4T}{\mu }}\] \[\therefore \] Hence, the ratio of frequencies \[\frac{{{v}_{1}}}{{{v}_{2}}}=1:1\]
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