A) \[0.075\,N\]
B) \[1.5\times {{10}^{-2}}N\]
C) \[0.225\,N\]
D) \[2.25\times {{10}^{-2}}\,N\]
Correct Answer: D
Solution :
Given that surface tension = 0.075 N/m; diameter = 30 cm = 0.30 m \[\therefore \] Force \[=0.075\times 0.30=0.0225\,N=2.25\times {{10}^{-2}}N\]
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