A) 8.0
B) 7.1
C) 6.9
D) 6.0
Correct Answer: C
Solution :
\[[{{H}^{+}}]={{10}^{-8}}M\](from HCl dissociation) \[+{{10}^{-7}}M\](from \[{{H}_{2}}O\] dissociation) \[=1.1\times {{10}^{-7}}\] \[\therefore \]\[pH=-\log [{{H}^{+}}]\] \[=-\log (1.1\times {{10}^{-7}})\simeq 6.9\]
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