A) \[\sqrt{\frac{h}{2\pi }}\]
B) \[\frac{1}{m}\sqrt{\frac{h}{\pi }}\]
C) \[\sqrt{\frac{h}{\pi }}\]
D) \[\frac{1}{2m}\sqrt{\frac{h}{\pi }}\]
Correct Answer: D
Solution :
Given \[\Delta x.\Delta p=\frac{h}{4.\pi }\] \[{{(\Delta p)}^{2}}={{(\Delta x)}^{2}}=\frac{h}{4\pi }\] \[(\Delta p)=\sqrt{\frac{h}{4\pi }}\] \[m\Delta v=\frac{1}{2}\sqrt{\frac{h}{\pi }}=\frac{1}{2m}\times \sqrt{\frac{h}{\pi }}\]
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