A) 8.7 MeV
B) 11.4 MeV
C) 10,2 MeV
D) 9.3 MeV
Correct Answer: C
Solution :
The radius of C-12 nucleus is \[R={{R}_{0}}{{A}^{1/3}}\] \[=(1.1){{(12)}^{1/3}}=2.52fm\] The separation between the centres of the nuclei is 2R = 5.04 fm The potential energy of the pair is \[V=\frac{{{q}_{1}}{{q}_{2}}}{4\pi {{\varepsilon }_{0}}r}\] \[=\frac{9\times {{10}^{9}}\times 6\times 1.6\times {{10}^{-19}}}{5.04\times {{10}^{-16}}}\]\[=1.64\times {{10}^{-12}}=10.2MeV\]
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