A) \[({{n}^{2}}+1)f\]
B) \[\left( \frac{n+1}{n} \right)f\]
C) \[\left( \frac{{{n}^{2}}}{{{n}^{2}}+1} \right)\times \frac{1}{f}\]
D) None of these
Correct Answer: B
Solution :
The minor formula is\[\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\] While, v = nu it can be \[\frac{1}{nu}+\frac{1}{u}=\frac{1}{f}\] \[\Rightarrow \]\[\frac{1+n}{nu}=\frac{1}{f}\]\[\therefore \]\[u=\left( \frac{n+1}{n} \right)f\]
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