VMMC VMMC Medical Solved Paper-2015

  • question_answer
    The minimum distance between the parallel planes of a crystal is 0.3 nm For the Bragg's scattering of X-ray of  \[0.3\overset{o}{\mathop{A}}\,\], would be given by

    A) \[\sin \theta =0.05\]rad

    B) \[\cos \theta =0.02\]rad

    C) \[\sin \theta =0.7\]rad  

    D) \[\tan \theta =0.7\]rad

    Correct Answer: A

    Solution :

     The Bragg's equation is\[2d\sin \theta =n\lambda \]where, a =1, 2, 3, ......and \[\theta =\] scattering angle \[\Rightarrow \]\[\sin \theta =\frac{n\lambda }{2d}\] Putting, n = 1 for minimum angle of scattering \[\sin \theta =\frac{1\times 0.3\times {{10}^{-10}}}{2\times 03\times {{10}^{-9}}}=0.05\]rad


You need to login to perform this action.
You will be redirected in 3 sec spinner