VMMC VMMC Medical Solved Paper-2015

  • question_answer
    Two light emitting sources of wavelength 500 nm are separated   by a distance 2.2 x \[{{10}^{2}}\] cm. A detector can be moved on the line \[{{S}_{1}}{{S}_{2}}\] is perpendicular to \[{{S}_{1}}{{S}_{2}}\] as shown in figure below. The minimum and maximum path difference at the detector as it is moved along the line\[{{S}_{1}}P\]are (respectively)                     

    A) zero,\[2.2\times {{10}^{-2}}cm\]              

    B) zero,\[1.1\times {{10}^{-2}}cm\]

    C) zero, zero                           

    D) \[2.2\times {{10}^{-2}}cm,2.2\times {{10}^{-2}}cm\]

    Correct Answer: A

    Solution :

    The path difference is maximum  when the detector is just at the position of \[{{S}_{1}}\] and its value is equal to \[2.2\times {{10}^{-2}},\] i.e. the separation between the sources. The path difference is minimum when the detector is at a large distance from \[{{S}_{1}}.\] In this case path difference is close to zero.


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