A) \[19.6\times {{10}^{20}}\text{N}{{\text{m}}^{-2}}\]
B) \[19.6\times {{10}^{18}}\text{N}{{\text{m}}^{-2}}\]
C) \[19.6\times {{10}^{10}}\text{N}{{\text{m}}^{-2}}\]
D) \[19.6\times {{10}^{15}}\text{N}{{\text{m}}^{-2}}\]
Correct Answer: C
Solution :
Young's modulus of material of the body is \[Y=\frac{\text{longitudial}\,\text{stress}}{\text{longitudinal}\,\text{strain}}=\frac{MgL}{Al}\] Putting the numerical values, we have \[L=2m,A=50m{{m}^{2}}=50\times {{10}^{-6}}{{m}^{2}}\] \[l=0.5mm=0.5\times {{10}^{-3}}m,M=250kg\] \[\therefore \]\[Y=\frac{250\times 9.8\times 2}{50\times {{10}^{-6}}\times 0.5\times {{10}^{-3}}}=19.6\times {{10}^{10}}N{{m}^{-2}}\]
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