2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2013

  • question_answer
    On the basis of the fact that \[NaN{{H}_{2}}\]can deprotonate \[HC\equiv CH\]but not \[C{{H}_{2}}=C{{H}_{2}}\]and the hybridization effect, order the following. four acids according to acidity \[\underset{I}{\mathop{HC\equiv CH}}\,\underset{II}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\underset{III}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,\underset{IV}{\mathop{N{{H}_{3}}}}\,\]

    A)  IV < III < II < I                                                     

    B)  III < 11 < IV < I                         

    C)  I < IV < II < III

    D)  III < IV < II < I                                                  

    Correct Answer: B

    Solution :

     Since, \[NH_{2}^{-}\]can deprotonate \[HC\equiv CH,N{{H}_{3}}\]is weaker acid than \[HC\equiv CH.\]On the other hand, \[NH_{2}^{-}\]cannot deprotonate \[C{{H}_{2}}=C{{H}_{2}}\]therefore \[N{{H}_{3}}\] is stronger acid than ethane. Ethane is weakest acid due to hybridisation effect.


You need to login to perform this action.
You will be redirected in 3 sec spinner