A) \[8.4\times {{10}^{-12}}\]
B) \[1.68\times {{10}^{-13}}\]
C) \[6.6\times {{10}^{-8}}\]
D) \[1.6\times {{10}^{-2}}\]
Correct Answer: A
Solution :
\[A{{g}_{2}}C{{O}_{3}}\rightleftharpoons 2A{{g}^{+}}+CO_{3}^{2-}\] \[[A{{g}^{+}}]=2.56\times {{.0}^{-4}}M\] \[[CO_{3}^{2-}]=\frac{[A{{g}^{+}}]}{2}=1.28\times {{10}^{-4}}M\] \[{{K}_{sp}}={{[A{{g}^{+}}]}^{2}}[CO_{3}^{2-}]\] \[={{(2.56\,\times \,{{10}^{-4}})}^{2}}(128\times {{10}^{-4}})\] \[=8.4\times {{10}^{-12}}\]
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