A) 270 mL
B) 90 mL
C) 405 mL
D) 135 mL
Correct Answer: C
Solution :
\[{{p}_{1}}{{V}_{1}}={{n}_{1}}R{{T}_{1}}\] \[{{p}_{2}}{{V}_{2}}={{n}_{2}}R{{T}_{2}}\] \[\frac{{{p}_{1}}}{9}{{V}_{2}}=\frac{{{n}_{1}}}{2}B(3{{T}_{1}})\] \[\frac{{{n}_{1}}R{{T}_{1}}}{{{V}_{1}}}=\frac{{{V}_{2}}}{9}=\frac{{{n}_{1}}}{2}R(3{{T}_{1}})\] \[{{V}_{2}}=\frac{27{{V}_{1}}}{2}=13.5\times 30\,mL\] \[=405\,mL\]
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