A) elimination reaction
B) electrophilic addition reaction
C) nucleophilic addition reaction
D) nucleophilic substitution reaction
Correct Answer: D
Solution :
\[\underset{\begin{smallmatrix} \text{Sod}\text{.}\,\text{tert}\text{.}\,\text{butoxide} \\ \text{(}{{\text{3}}^{\text{o}}}\,\text{alkoxide)} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-ONa}}\,+\underset{(i)\,alkyl\,bromide}{\mathop{C{{H}_{3}}Br}}\,\xrightarrow{\begin{smallmatrix} \text{Nucleophilic} \\ \text{Substitution} \end{smallmatrix}}\]\[\underset{tert.\,butyl\,ether}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OC{{H}_{3}}}}\,+NaBr\]
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